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Bar Bending Schedule of Lintel Beam
Bar Bending Schedule is actually a chart made and utilized for calculating reinforcement and steel for slab, column and beam.
Length of lintel = 3000 mm = 3 m
Breadth of lintel = 300 mm = 0.300 m
Lintel depth = 300 mm = 0.300 m
Concrete cover = 25 mm
Column width = 300 mm
Depth = 300 mm
Dia of main bars = 12 mm
There are 4 number main bars
Dia of steel of stirrup = 8 mm
200 mm centre to centre space is between two stirrups
Dia of stirrup = 8 mm @ 200 c/c
One bar length = Lintel length – Concrete cover = 3 – (2 x 0.025) = 2.95 m
Number of stirrups = Overall length of lintel/centre to centre distance + 1
Number of stirrups = Overall length of lintel/c/c distance + 1
= 3/0.200 + 1 = 16
One stirrup cutting length:–
Internal/Inner depth, D = 300 – 25 – 25 – 4 – 4 = 242 mm = 0.242 (in m) x 2 = 0.484 m (as there are 2 sides)
Width = 0.242 x 2 = 0.484 m
Hook length = 10d = 10 x 8 = 80 mm = 0.080 m
As there are two hooks, 2 x 0.080 = 0.16 m
One stirrup length = 0.484 + 0.484 + 0.16 = 1.128 m
Description | Diameter(mm) | No. | Length(m) | Total length(m) | Weight (kg/m) |
Total weight(kg) |
Remarks |
---|---|---|---|---|---|---|---|
Main bars | 12 | 4 | 2.95 | 11.8 | 0.88 | 10.48 | D2/162 x L = (12)2/162 x 11.8 = 10.48 kg |
Stirrups | 8 | 16 | 1.128 | 18.048 | 0.39 | 7.13 | D2/162 x L = (8)2/162 x 18.048 = 7.13 kg |
Total weight | 17.61 kg |
To get more information, watch the following video tutorial.
Lecturer: Civil Study