TUTORIALS

How to Calculate Number of Bricks, Quantity of Cement [bags] and Sand in a Brick Wall

Suppose mortar ratio is equal to 1:6, where 1 part is cement and 6 is for sand.

Mortar thickness is equal to 10 mm.

Constants are:

Cement density is equal to 1440 kg/m³
1 m³ is equal to 35.3147 ft³
Modular brick size volume [with no mortar] is equal to 0.19 x 0.09 x 0.09 = 0.001539 m³

Brick volume [with mortar] is equal to 0.20 x 0.10 x 0.10 = 0.002 m³
Number of bricks in 1 m³ volume is equal to 1/Brick volume [with mortar] = 1/0.002 = 500 bricks
Mortar wet volume is equal to 1 – 500 x brick volume [with no mortar] = 1 – 500 x 0.001539 = 0.2305 m³ [Wet volume]

Mortar dry volume is equal to 0.2305 x 1.33 = 0.306565 m³
Cement quantity is equal to 1/7 x mortar dry volume x cement density = 1/7 x 0.306565 x 1440 = 63 kg
Cement quantity [in bags] is equal to 63/50 = 1.26 bags = 2 bags

Sand quantity is equal to 6/7 x mortar dry volume = 6/7 x 0.306565 = 0.26277 m³
Changed in ft³ is equal to 0.26277 x 35.3147 = 9.28 ft³

Therefore, for 1 m³ volume
Overall number of bricks = 500 bricks

Cement quantity = 63 kg
Sand quantity = 2.78 ft³
Let’s calculate the amount of bricks, sand and cement to be utilized for the wall

Provided:

Wall dimension = 4 m x 5 m x 0.101 m
Number of bricks in the wall is equal to volume/brick volume [with mortar] = 4 x 5 x 0.101/0.002 = 1010 bricks

Mortar volume = (4 x 5 x 0.101) – (1010 x 0.001539) = 0.46 m³ [wet volume]
Mortar dry volume = 0.46 x 1.33 = 0.6118 m³
Cement quantity = 1/7 x 0.6118 x 1440 = 126 kg

Cement [in bags] = 126/50 = 3 bags
Sand quantity = 6/7 x 0.6118 [mortar dry volume] = 0.524 m³
Sand in cubic feet = 0.524 x 35.3147 = 18.52 ft³

Therefore, for 4 m x 5 m x 0.101 m wall:
Number of bricks = 1010 bricks
Cement quantity = 126 kg
Sand quantity = 18.52 ft³

To get more details, go through the following video tutorial.

Lecturer: TECH@7K