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How to Measure the Concrete Quantity in Isolated Footing

Description of Footing: Footings refer to the fundamental portion of foundations. Furthermore, they’re positioned beneath the ground level (Substructure). Moreover, footings are main RCC members in buildings.

Description of Isolated Footing: Isolated Footing is primarily located beneath the column as well as the entire load is distributed to the footing and next distributed to the soil. Also, the isolated footing is known as trapezoidal footing.

Procedure to calculate the concrete volume of isolated footing:

In order to calculate the volume of concrete of isolated footing; firstly, it is needed to find out the dimensions of isolated footing.

Moreover, in architectural drawings, the subsequent sorts of views are present: Plan or Top View, Elevation or Cross Section View.

The objective of the top view is to determine the area that is length as well as breadth of a specified footing.

Also, the purpose of cross section view of a structure is to figure out the thickness/height of the structure as well as it is primarily utilized for Reinforcement detailing of the structure.

Moreover, the volume of concrete in isolated footing is calculated in the subsequent 2 methods:

V1, it signifies the volume of the base of the isolated footing.

V2, it signifies the volume of the trapezoidal portion.

Calculate the volume of concrete in V1

Furthermore, volume V1 is equal to L x B x H1

In this respect, H1 signifies the height of the base portion

Furthermore, L signifies the length of footing

Moreover, B signifies the breadth of footing

Also, volume V1 is equal to 1200 x 1000 x 200 = 240000000 mm 3 or it is equal to 0.24 cum.

At this point, calculate the volume of concrete in V2

Furthermore, volume V2 = H/3 (A1 + A2 + √(A1 x A2))

In this respect, A1 signifies the area of bottom of footing

Moreover, A2 signifies the area of top of footing

At this point, the values of A1 and A2 are going to be calculated in the following way:

A1 = L x B

= 1200 x 1000

= 1200000 mm² or it is equal to 1.2 m 2/p>

A2 = L1 x B1

= 600 x 500

= 300000 mm² or it is equal to 0.3 cum

At this point, H = H2 – H1

= 450 – 200

= 250 mm or it is equal to 0.25 m

So as to figure out the volume of isolated footing V2 portion in m 3 , specify the values of A1 as well as A2 in the subsequent formula:

V2 = H/3 (A1 + A2 +(√(A1 x A2))

= 0.25/3((1.2+0.3) + √(1.2x 0.3))

= 0.0833((1.5) + (0.6))

= 0.1749 cum

Overall Volume, V = V1 + V2

V is equal to 0.24 + 0.1749

V is equal to 0.414 cum

To get more clear ideas, go through the following video tutorial presented by the renowned engineer S.L. Khan.

Lecturer: Engineer Boy